cs Sep 4, 2014

identifier which does not have memory : void f()

int main()
{
   f() ; f is called, () is the functional operator
}

main is a definition while f is a declaration..

define f now :: list out what it does..

declaration " associate a type with an identifier"
definition " this also allocates memory", (creates an object)

string s; //definition

declaration which is not a definition for a variable ?

class Myclass; //declaration  only.
class Mathclass{ }; //declaration only

variable declaration  which is not a definition..

initialization -- gives the object a value.

[]  square brackets;

<> angle brackets
{} curly braces

type -unsafe allows implicit conversions
type-safe -- does not allow implicit conversions

g++ option for c++11
flag -std=c++11

REN project

create a new type : class Mathclass {  };
data definition not a declaration

void f(int x);  (not definition, only declaration of x here)
{
}
how to add code to the above so we allocate memory to it.
f(2); allocates memory.

struct s {int x ; }; creating a new type , declaring x to be an integer within it., still not an object and no memory allocated.

can't do struct s{int x=2;}; as this does not have a memory.

Example of string literal : "hello" object with no name
eg. of numeric literal : 2
character literal : 'a'

Not every unnamed object is a literal but all literals

unnamed object which is not an identifier.

new int; basically unnamed object but not an identifier. allocates memory.

new int(2); allocating memory and initialize this.. initializing an unnamed object.

cout << new int(2) ;; would display the memory address where the object was allocated.
cout << * new int(2) ;   dereferencing operator..

int *p = new int(2);

cout<<*p;

compiletc from the list of apps install.